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Best choice of discretization in RF problems; quadratic, linear, or?

Robert Koslover Certified Consultant

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The default element discretization in the RF module is quadratic. However, I have found in my own work that changing it to linear and (but only if necessary) increasing the number of elements to maintain accuracy, actually yields faster computations and consumes less memory. So... why does Comsol assign quadratic as the default? Are there any hidden risks associated with using linear elements instead?

1 Reply Last Post Nov 4, 2011, 4:17 p.m. EDT
Ivar KJELBERG COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)

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Posted: 1 decade ago Nov 4, 2011, 4:17 p.m. EDT
Hi

Interesting observation, thanks, I have definitively NOT the final answer, I believe we need a comment from someone from COMSOL for that, but with quadratic values you get better derivatives values, so I suppose it depends also on what kind of post-processing you want to do.

--
Good luck
Ivar
Hi Interesting observation, thanks, I have definitively NOT the final answer, I believe we need a comment from someone from COMSOL for that, but with quadratic values you get better derivatives values, so I suppose it depends also on what kind of post-processing you want to do. -- Good luck Ivar

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